Question

Processing the Data: A) Standardization of the NaOH Solution: Trial 1 Trial 3 Trial 4 Trial 2 6.62004 O.02001 0.01207 Volume

When a solution of a strong acid is mixed with a solution of a strong base, a chemical reaction occurs that can be represente

how to get molarity of HCl and H+ with provided numbers and equation, not sure how to get molarity with just volumes (this was done through titration) thanks.

EDIT: From what I can see molarity of HCl is not provided by buy NaOH is 6M? Not sure if that helps..

molarity of NaOH is 6M

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Answer #1

Trial 1 Molasity NaOH = GM Volume HCL = 0.02004 L Volume NaoH = 0.019 005 L Hil+ Naoh Naci ttho NaoH HOL 6MX 0.0190051 - MX

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