Question

Consider a different analyte for this exercise. Citric acid is found in many fruits and fruit juices. Sodium hydroxide (NaOH) is the titrant and citric acid (H₃C₆H₅O₇) the analyte according to the following balanced chemical equation.

H₃C₆H₅O₇ + 3 OH⁻ → C₆H₅O₇³⁻ + 3 H₂O

(a) What is the stoichiometry of H₃C₆H₅O₇ to OH⁻?

Options are: 8:3, 5:2, 3:1, 1:1, 1:3, 2:5, 3:8

(b) Complete the following table for this titration.

Data Table P2: Titration of citric acid in orange juice with sodium hydroxide.

concentration of OH−	0.0702 M
volume orange juice	8.65 mL
mass orange juice	8.79 g
volume of OH− solution	27.58 mL
mmol of OH−	.... mmol
mmol of H3C6H5O7	.... mmol
mass of H3C6H5O7	..... g
mass % of H3C6H5O7 in orange juice	..... %
molarity of H3C6H5O7 in orange juice	..... M

Answer 1

mmole. 1.93€ Mas 124 H3C Hg Hy o7 : OH = 1:3 Answer [1:3) mmol of OH = 27.58 ml x 0.0702 mole/ = 11.96 monot of @ H3 Catts Of = 1.33€ – 10.645 mmole. mass of H₂ C H5O7 = 0. 645 mpole x 192.124 Imole = 10.124/ a Mass % of H₂ { HS og in orange 0.124 x 100 Juice = = 1.411% Molarity of H3 GHz Of in orange Juice - 0.645 8.65 - 10.0746 m 8.79