Question

Consider a different analyte for this exercise. Citric acid is found in many fruits and fruit juices. Sodium hydroxide (NaOH) is the titrant and citric acid (H2C6H507) the analyte according to the following balanced chemical equation. H3C6H507 + 3OH- → C6H50,3- + 3 H20 (a) What is the stoichiometry of H3C6H507 to OH ? UN OOOOOOO (b) Complete the following table for this titration. Data Table P2: Titration of citric acid in orange juice with sodium hydroxide. concentration of OH- volume orange juice mass orange juice volume of OH-solution mmol of OH- 4.0 mmol of H3C6H507 4.0 mass of H3C6H507 mass % of H3C6H50, in orange juice 4.0 molarity of H3C6H507 in orange juice 49) 0.0758 M 8.83 mL 8.98 g 23.24 mL mmol mmol g M

Answer 1

H3 CHg Of + 3.014 CH 50 / 4 + 3H₂O. a) Total no. of each elementale; Ho) as well as the charge is equal on both sides. So, the above equation is balanced equation. 1 mol of H₃ CHE of is neutralized with smol of Ohio. so, the stoichiometry of H3 CHg Og to oh is 1:3. (6) Concentration of on = 0.0758 (M) ... volume of our solution = 23.24 mL volume of orange Juice = 8.83 mL mass of organige Juice = 8.989: Citric acid (H₂ C. HE 07) is present in the orange Juice. Similarly other organic compounds are also present in orange Juice. When we add NaOH solution, only citrie acid gets titrated. So we only calculate the acid . concentration in orange Juice. ÕH concentration = 0.0758 (M) .. 1000 mL solution contains 0.0758 mol of Naoh I mL . 0.0758 ? ? 23:24 mL , 10oo.. ..! 0.0758X23.24 -mot mot T 1.000 1 23.24 mL of 0.0758 (M) oh solution - 1.762 x 10² mol. I contains t. 762 mmol õh : = 1.762 mmol.

According to the chemical equation as well as the Amieloma kғХ of H, енд 01 +о он, ... 3 mol ön neubralizes Imol the H5O7. I 31 13 şu ». : 1.762x10 mols 1x1762x103 3 3.0.587 x vý? mot. Immol = 103 mol = 0.587 mmol. Hy CoHg 07. In the titration reaction, There its 0.587 mmol of H₃ C H5O7. Now, molar mass of H₂ C6H5 07: : (3x1) + (6x12)+(541) + (7xib) gmot! = 3+72+ 5.+112 = 192 g mot ::= 0.5878103 mol x 1929 moi 3 0.113 g . The ong orange Juice of 8.83 mL contains 0.587 mmol : le 0.1139 of citric acid. But the total mass of 8.83 mL Juice = 8.98 g. That. at supports the presente of other compounds

8.98 excepting citric acid. Therefore, 8.98 g orange Juice contains 0.113 geitric acid. I a. 1 . v 0.113 20...! toog Blu 0.113.x100 mm 8.98 = 1.258.9 w & Massy of the GHG of in orange Juice = 1.258% Again, 8. 83 mL Juice contains 0.5878103 mot the 145 of 1. B is 0.587X163 » in 1000 mL . - 8.83 0.587x10²x1000 in 18.83 :=0.0665 mol H₂ CH2O7. : Molarity of H ₂ C GH507 in Orange Juice=0.0665(M) . (Molarity 2 no. of miles of solute per 1000mL): mmol of oh oh 1.762 mmol mmol of Pz Cq Hg Of . 0.587 mmol i mass of H3C Hg 07: 0.113 g . massy of tz C Hg Of in orange Juice 1:258 7. molarity of the CG H5O7 in Orange Juice 0.0665 (M)