Question

Experiment #7. Titration of Vinegar Goals 1. To determine the mass percent of acetic acid in a solution via titration. 2. To master the technique of titration. Introduction Vinegar is a common household item that is found in a number of products from salad dressing to cleaners. Vinegar is a solution of acetic acid (CH COOH or HC,H:O2) in water. The amount of acetic acid is usually 5 % by mass in the vinegar solution. In this experiment, you will determine the mass percent of acetic acid in vinegar by titration Titration is a common method used by chemists to find the concentration of a substance in a solution. Titration involves two key components: the titrant and the analyte. The titrant is a solution of known concentration which is used to find the concentration of the analyte, a solution of unknown concentration. Acid-base titrations are the most common type of titration. If the analyte is an acid, then the titrant is a base. The titrant would be added to the analyte until all of the acid is neutralized this is known as the equivalence point or end point. At the equivalence point, the number of moles of acid (H) is equal to the number of moles of the base (OH Hbased on stoichiometry). By carefully measuring the amount of titrant used, you can determine the number of moles of acid present The easiest way to determine the equivalence point of the reaction taking place is to use a visual indicator. Visual indicators change color at different pH. For this titration the indicator is phenolphthalein, which changes from colorless (pH < 8) to pink (pH> 8). The analyte for this experiment is the acetic acid in vinegar with pH less than 7. Our titrant will be sodium hydroxide, a base. When enough titrant, NaOH, is added to neutralize the acetic acid, the solution will change from colorless to just barely pink in color. NaOH(aq HC,H,O:(aq) HO() NaC,H,0, (aq) In titrations, it is important that you measure all volumes precisely. You must know the exact amount (to 0.01 mL) of NaOH(aq) required to react with the HCH,02 as well as the amount of HC H,O, you began with. The reaction of NaOH with HC;H,0, is 1:1 stoichiometricaly. Since you will measure the volume of NaOH(aq) added and be given the molar concentration of the NaOH, you can find the moles of NaOH. The moles of NaOH will be equal to the moles of HC,H,O, in the solution. To get percent by mass of HC:H,0: in vinegar, you will need to know the molar mass of the HCH)O, and the mass of the vinegar sample. Laboratory Activity Materials: 2 x 125 mL Erlenmeyer flasks vinegar deionized water 50 mL buret 200 or 250 mL beaker phenolphthalein standardized NaOH (aq) buret stand and holder funnel Procedure 1. Rinse a 50 mL buret two or three times with deionized water. Be sure to let the water run out of the tip 2. Remove traces of water from the buret by rinsing with NaOHlaq): add twD pipettes' worth (approximately 2 mL) of NaOH(aq) to the buret. Drain some NaOH(aq) out af tip then pour the rest out of the top into the sink, rotating as vou pour to coat the sides with the salution. Repeat with another 2 mL portion of NaOHlan) 3. Fill the buret with the NaOH solution until the volume reads a little above the 0.00 ml line. Drain the buret into a waste beaker until the buret reads 0.00 mL. The tip of the buret should be completely filled with solution-any air bubbles present will interfere with your measurements. If there is an air bubble in the tip, continue draining until the bubble comes out then refill the buret to 0.00 mL.

The table filled is the lab run.
Please can you use the three informations provided above to answer the empty table

Take Density of vinegar = 1.005g/mol

concentration of NaOH = 0.1205M

Answer 1

For run Volume a Naon used 13-6omL O-00 mi 13-6 foam balanced equohog moles CHcaaH Cinim negau 7 moles बोरैव O205 moles 13-69ms 20-0016 388rae O-001639 moles mole Cn 3 Agues t0.00l639 of chcooH mass ndles 7 molar mass 2 0-001639 moles 6o -o52 9/mo pevcent by mass mass of c coor mass ot nega negav volome o densy mass 20 p1-0059 ML 2.0ls 9 by mass percent 2-019 4-9010 2