1) When the amount of vinegar is measured, we can calculate the strength using the data. No matter what amount of water we add , it won't change the amount of base needed to standardise the sample solution taken for titration. The base reacts in one to one molar ratio which means it deals with the no of moles present in the solution. The amount of water added won't change the amount of mole present.
2 ) We use pipette to measure a fixed amount of sample solution to be titrated. If it already contains some amount of water, the the actual amount of sample would be less and the concentration will be lower than usual.
3 ) The concentration of acetic acid in vinegar is too high . If the volumetric flask contains a little amount of water , then it won't change the concentration too diversely. Though, the actual concentration will be lower as the mark of volumetric flask will reach early if it contains some amount of water.
4 ) Let , the concentration of the solution is X moles per liter.
The molar mass of acetic acid is 60 g per mole. Density is 1.0052 g/mL.
So, using the formula ( grams of sample present/ grams of solution) * 100 = % (m/m)
(x * 60*100 )/(1.0052*1000) = 1.55
x = ( 1.55 * 1000 * 1.0052)/ 6000 = 0.25 M
The concentration is 0.25 M
I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The...
Need help someone please help me like right now.thank you in advance!!!!!! VALUE Volume original vinegar solution Volume diluted vinegar solution Dilution Factor Molarity of NaOH SD 5 ml DZAM TRIAL 1 TRIAL 2 TRIAL 3 HL 10.00mL 0.0 ML SolomL 15. lom 11. 5. 110. 20ml 5.10mL In 10.20m 15. Gou 5.20ml Volume of diluted vinegar sample used in each titration (mL) #2 Initial buret reading (mL) Final buret reading (ml) Volume of NaOH Moles of NaOH Moles of...
chem 110 experiment 12 tritation vinegar need help fast please!!! The density of vinegar is 1.01 g/mL. How would this information affect your experimental results. 2. Weak acids, such as acetic acid, typically have an odor, whereas strong acids often do not. Explain this is so EXPERIMENT # 1 2 ACETIC ACID CONTENT OF VINEGAR Objectives Use chemical pll indicators to find endpoints of acid base titrations Use the burets to undertake chemical titrations PreLab questions i. Lab. If commercial...
Exp 9 titration of vinegar procedure b molarity of NaOH = .0859 ROCEDURE B. DETERMINATION OF CONCENTRATION OF ACETIC ACID IN UNKNOWN SAMPLES Titration of vinegar solutions Trial 1 Trial 2 Trial 3 1. Volume of vinegar solution being titrated in milliliters (mL) 25.00 mL 25.00 mL 25.00 ml 2. Volume of vinegar solution being titrated in Liters (L) 0.0250 L 0.0250 L 0.0250 L 3. Final buret reading in ml 16. 20m 16.316L 16.25ml 4. Initial buret reading in...
i need all answers Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
I need help calculating the mass percent and with the post lab question #2. Part 1 Mass Initial | Final Vol Nall Moles concen. KPHCG (ML) I (m2) Used (m2) KHP (mol)/NaOH(M) 0.28470.00 13.60r 13.600 10.00- 0.1025 2 UZ + ZANT 13.600 24.45 1 10.85 0.001128 10.40 Aug NaOH Concentration (M):0.1032 Part2 Vinegar identification # 4 Vinegar sample date: (011/ Vol Vinegat Initial Final Yol NaOH Mol Acotic Mass Acctic Mass % Titr ULST I OML Used (ml) Acid (mol)...
WIJNLIUH Compartir Ventana Ayuda Vinegar Lab Report a página Figura Multimedia Comentario Insertar Tabla Gráfica Texto Laboratory Report -Titration of Vinegar Type Name Here: Go Colaborar Run 1 Run 2 Run 3 2.00 mL 2.00 mL 0.100 M 0.100 M Volume of Vinegar Used Concentration of NaOH Initial Buret reading Final Buret reading Volume of NaOH Used (Final Buret reading - Initial Buret reading) 2.00 mL 0.100 M 1.180 mL 0.05 ml 16.04 ml 0.25 ml 16.92 mL 17.38 ml...
For vinegar titration in this experiment, would the following errors cause the % acetic acid in vinegar determined to be (A) too large, (B) too small, (C) no effect, or (D) not enough information to answer. Assume that the mistake given is the only mistake made in the experiment. EXPLAIN. 1.) The burst is rinsed with distilled water, but not NaOH solution before the vinegar sample is titrated. 2.) After standardization, the NaOH solution is not stoppered and obsorbs CO2...
The table filled is the lab run. Please can you use the three informations provided above to answer the empty table Take Density of vinegar = 1.005g/mol concentration of NaOH = 0.1205M Experiment #7. Titration of Vinegar Goals 1. To determine the mass percent of acetic acid in a solution via titration. 2. To master the technique of titration. Introduction Vinegar is a common household item that is found in a number of products from salad dressing to cleaners. Vinegar...
..ll GoSmart 9:18 PM 7 73% Х CHM 103 Lab 3 Acid Base... + U Experiment 3 ACIDS AND BASES: ANALYSIS Learning Objectives Upon completion of this experiment, Mudents will have experienced 1. The determination of the percent by mass of acetic acid in vinegar 2. The determination of the molecular mass of an unknown acid Text Toples Acids and buses, indicators, titrations Notes to Students and Instructor The solution of sodium hydroxide prepared last week will be used to...
1. In the second step she prepared the vinegar solution for the titration in the following manner 25.0 mL of vinegar were diluted to 250.0 mL in a volumetric flask, and 25.0 mL of this diluted solu- tion required 8.27 mL of the above standardized NaOH (gquestion 5a) to reach the phenolphthalein endpoint. What is the molarity of the acid as it was titrated (diluted vinegar)? a. Use the dilution equation to determine the molarity of the acid prior to...