Question

WIJNLIUH Compartir Ventana Ayuda Vinegar Lab Report a página Figura Multimedia Comentario Insertar Tabla Gráfica Texto Laboratory Report -Titration of Vinegar Type Name Here: Go Colaborar Run 1 Run 2 Run 3 2.00 mL 2.00 mL 0.100 M 0.100 M Volume of Vinegar Used Concentration of NaOH Initial Buret reading Final Buret reading Volume of NaOH Used (Final Buret reading - Initial Buret reading) 2.00 mL 0.100 M 1.180 mL 0.05 ml 16.04 ml 0.25 ml 16.92 mL 17.38 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for cach run. 2. Calculate the number of moles of acid in each sample. 3. Using your answer to calculation 2, calculate the molarity of the vinegar sample for each run. 4. Calculate the average molarity of the vinegar. 5. The true concentration of the vinegar is 5.00g/100mL of vinegar. Calculate the true molarity of the vinegar.

Answer 1

Calculations-

U HUU Multimedia Comentario Laboratory Report - Titration of Vinegar Type Name Here: Run! Run 2 Run 3 2.00 mL 2.00 mL 0.100 M 0.100 M Volume of Vinegar Used 2.00 ml Concentration of NaOH 0.100 M Initial Buret reading 0.05 ml Final Buret reading 16.04 ml Volume of NaOH Used (Final Buret reading - 16.04-0.05= 15.99 Initial Buret reading) mL 1.180 mL 0.25 mL 16.92 mL 17.38 ml 16.92 -0.25= 16.67 mL 17.38-1.18= 16.2 mL Calculations

calculation : No. of moles of bone stequired molewiły x Vasot CinL) No. * bone required = ^ Run-1: Oii mol x 0.01599 -16 X10-3 mol Noolt Run- 2 0 1 mol xocoLGG 7 K = 17X10 í 7x10-3 mo No он Km-3 ; 01 mol x. 0.0162 K 2 1.6 X 10 mal Noolt @ In this, titsation — No.of moles of Naot = mo oh as they react in il reatio- etz.co0H + Araot = ctz ccona + Hao i No. of moles et'add" : ' Run-) Run-2 Run 3 16x1073 17X10 -3 16610-3 moles moles . moles

Mobily of vinegemea mele af a(mas negar- OM g yon vinegar (in L) Now, Voimegon= 2mL - 2810-86 " Ruml: Mvinegar 16x10- Zmode 2x10-31 = 0.8(M) Run 2 : = 0.85(M). Run 3 Mvinegar = 17x10-3 mode 2 x 10-3 1 : 16x10-3 mol 2x10-31 Mrinegar - 2x10 - = 0.8(M) @ Avezoge molersity of winger 2 o5to as to: imo Vinea 2 0.82(14 (rounded off) 6. Molevity is exprened in mole, . bH sos = 59 " 20.0833 mol /(M. Macetic acid 60-052 g/mol L = 60.0527 True molarity 0.08 33 mol 0.0833 mol 07" Ivom L = 0 0.83(M) all