Homework Answers
- Calculate Number of moles of base (NaOH)
Vinegar = Acetic acid (CH3COOH)
Volume of Vinegar used = 2.00 mL
Run 1:
Concentration of NaOH used = 0.100 M
Volume of NaOH used = 18.25 mL
0.100 N = 
x = 0.073 gm (given weight)
Number of moles = Given weight/ Molecular Weight
Number of moles = 0.073/40 = 0.001825 moles
Run 2 :
Concentration of NaOH used = 0.100 M
Volume of NaOH used = 17.10 mL
0.100 N = 
x = 0.068 gm (given weight)
Number of moles = Given weight/ Molecular Weight
Number of moles = 0.073/40 = 0.00171 moles
Run 3:
Concentration of NaOH used = 0.100 M
Volume of NaOH used = 17.10 mL
0.100 N = 
x = 0.0674 gm (given weight)
Number of moles = Given weight/ Molecular Weight
Number of moles = 0.073/40 = 0.001687 moles
- Calculate Number of moles of acid (CH3COOH)
Run 1:
CH3COOH = NaOH
N1 V1 = N2 V2
(Acid) = (Base)
N1 X 2.00mL = 0.100 x 18.25
N1 = 0.9125 N
Concentration of CH3COOH used = 0.9125 N
Volume of CH3COOH used = 2.00 mL
0.9125 N = 
x = 0.1095 gm (given weight)
Number of moles = Given weight/ Molecular Weight
Number of moles = 0.1095/60 = 0.001825 moles
Run 2:
CH3COOH = NaOH
N1 V1 = N2 V2
(Acid) = (Base)
N1 X 2.00mL = 0.100 x 17.10
N1 = 0.855 N
Concentration of CH3COOH used = 0.855 N
Volume of CH3COOH used = 2.00 mL
0.855 N = 
x = 0.1026 gm (given weight)
Number of moles = Given weight/ Molecular Weight
Number of moles = 0.1026/60 = 0.00171 moles
Run 3:
CH3COOH = NaOH
N1 V1 = N2 V2
(Acid) = (Base)
N1 X 2.00mL = 0.100 x 16.87
N1 = 0.843 N
Concentration of CH3COOH used = 0.843 N
Volume of CH3COOH used = 2.00 mL
0.843 N = 
x = 0.1012 gm (given weight)
Number of moles = Given weight/ Molecular Weight
Number of moles = 0.1012/60 = 0.00168 moles
- Calculate the molarity of each vinegar sample
Run 1:
CH3COOH = NaOH
N1 V1 = N2 V2
(Acid) = (Base)
N1 X 2.00mL = 0.100 x 18.25
N1 = 0.9125 N
Run 2:
CH3COOH = NaOH
N1 V1 = N2 V2
(Acid) = (Base)
N1 X 2.00mL = 0.100 x 17.10
N1 = 0.855 N
Run 3:
CH3COOH = NaOH
N1 V1 = N2 V2
(Acid) = (Base)
N1 X 2.00mL = 0.100 x 16.87
N1 = 0.843 N
Acetic cid or vinegar is a monobasic acid hence, normality and molarity are equal
Add Answer to:
question 3
Run 1 Volume of Vinegar Used 2.00 mot Concentration of NaOH Name maura alarener...
question 2 Laboratory Report Titration 1 11FSI Name maura Quarenga Run 1 Run 2 Volume of...
question 2
Laboratory Report Titration 1 11FSI Name maura Quarenga Run 1 Run 2 Volume of Vinegar Used Concentration of NaOH Run 3 0.100 M Initial Buret reading 0.100 M Final Buret reading 19.68 m Volume of NaOH Used 0.01sas L (Final Buret reading - 1.18.25 Initial Buret reading) 7 2.00 mL 0.100 M L 1 19.68 ml 107.69 mil 360.78 m 2 . Scom 10.017 I L 10.016872 MolML 1 16.87 ML Calculations: 1. Calculate the number moles of...
question 1 Divool Laboratory Report Titration Name maura alarenga Run 1 Run 2 Run 3 Volume...
question 1
Divool Laboratory Report Titration Name maura alarenga Run 1 Run 2 Run 3 Volume of Vinegar Used 2.00 mL oor meerlac | Concentration of NaOH 0.100 M 0.100 M 0.100 M Initial Buret reading 1.43mc 19.68 ml 107.69 m2 Final Buret reading 19.68 m 36.78m lau. som Volume of NaOH Used $.isas L 10.017 0.016872 (Final Buret reading - 8.25 m 17 olme lah 16.87 Initial Buret reading) 1 AL Calculations: 1. Calculate the number moles of base...
question 4 Laboratory Report Titration Run 1 Run 3 Volume of Vinegar Used Concentration of NaOH...
question 4
Laboratory Report Titration Run 1 Run 3 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.49 m Final Buret reading 19.68 m Volume of NaOH Used .01sasl (Final Buret reading - 1.18.a Initial Buret reading) Name maura awarenes Run 2 dac 0.220 0.100 M 0.100 M 19.68 ml €7.6mu 360.78 m 10.017 0.01€ 872 117 .me com 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each...
question 6 UUTUUDIY Report Titration Run 1 Run 3 Name Laura A cense Run 2 Volume...
question 6
UUTUUDIY Report Titration Run 1 Run 3 Name Laura A cense Run 2 Volume of Vinegar Used o radac Concentration of NaOH 0.100 M 0.100 M 0.100 M 1.45 mL 1 1 19.68 ml 107.69 m2 Final Buret reading 19.68 m 36.78me lauo some Volume of NaOH Used 6.01sas 0.01710 0,ole 871 (Final Buret reading - 18.a I rolML 18h 16.87 Initial Buret reading) Calculations: 1. Calculate the number moles of base required to reach the endpoint for...
question 5 Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used...
question 5
Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.43 me Final Buret reading - 19.68 m Volume of NaOH Used 0.01sas (Final Buret reading - 1.18.25 Initial Buret reading) to Run 3 Dodac opet 0.100 M 0.100 M 119.68ml 107.69mil 36.78me. lau. Some 0.0171 0.016872 Boh 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each run....
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used...
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used in each trial = 0.20M 3. Volume of NaOH used in trail#1 (Final – Initial buret reading) = __17.80______ mL 4. Volume of NaOH used in trail#2 (Final – Initial buret reading) = ___18.20_____ mL 5. Average Volume of NaOH used = (#3 + #4) / 2 = ___18______ mL 6. Calculate Molarity of Acetic acid in vinegar = _________ M ?????? (molarity of...
WIJNLIUH Compartir Ventana Ayuda Vinegar Lab Report a página Figura Multimedia Comentario Insertar Tabla Gráfica Texto...
WIJNLIUH Compartir Ventana Ayuda Vinegar Lab Report a página Figura Multimedia Comentario Insertar Tabla Gráfica Texto Laboratory Report -Titration of Vinegar Type Name Here: Go Colaborar Run 1 Run 2 Run 3 2.00 mL 2.00 mL 0.100 M 0.100 M Volume of Vinegar Used Concentration of NaOH Initial Buret reading Final Buret reading Volume of NaOH Used (Final Buret reading - Initial Buret reading) 2.00 mL 0.100 M 1.180 mL 0.05 ml 16.04 ml 0.25 ml 16.92 mL 17.38 ml...
Quantitative Analysis of Vinegar via Titration Lab Team Members Quantitative Analysis of Vinegar via Titration Report...
Quantitative Analysis of Vinegar via Titration
Lab Team Members Quantitative Analysis of Vinegar via Titration Report Sheet 1 Part A: Standardizing a Dilute Sodium Hydroxide, NaOH(aq). Solution KHC,H,O,(aq) + NaOH(aq) + H2O(1) + KNaC,H,O,(aq) 204.22 g/mol Trial 1 Trial 2 Trial 3 10.33919 0.36769 0.35989 moles of KHP, mol moles of NaOH, mol initial buret reading, ml 4.00 ml 20.10 mi 30.10 m final buret reading, ml 19.30 ml 35.60m145.10 ml volume of NaOH, ml. volume of NaOH, LL [NaOH],...
Sample 1 .674a Sample 3 0.00 -63619_573989 Sample 2 Mass of KHP taken Initial NaOH buret...
Sample 1 .674a Sample 3 0.00 -63619_573989 Sample 2 Mass of KHP taken Initial NaOH buret reading c om m e Final NaOH buret reading 33. ML 32.30ml Volume of NaOH used 33 mL 32.3mL Moles of KHP present 003_ moles_003 mole s kup Molarity of NaOH solution 10 M Mean molarity of NaOH solution and average deviation 0 04 M اور * 5% vinesar Sample 2 WHO Analysis of Vinegar Solution (Part 4a) Identification number (or brand) of vinegar...
fill in 5-9 A. Preparation of Vinegar Sample Brand of vinegar Trial 1 Trial 2 1....
fill in 5-9
A. Preparation of Vinegar Sample Brand of vinegar Trial 1 Trial 2 1. Volume of vinegar used (mL) 2. Density of vinegar (g/mL) 3. Mass of vinegar used (g) solution - P.V. 5.0 1002 5.01 5.0 1.000 5.01 B. Analysis of Vinegar Sample 1. Buret reading of NaOH, initial (mL) 2. Buret reading of NaOH, final (mL) 3. Volume of NaOH used (mL) 0 0 43.60 46,90 42.60 41.90 1005 4. Molar concentration of NaOH (mol/L) 5....
question 2
Laboratory Report Titration 1 11FSI Name maura Quarenga Run 1 Run 2 Volume of Vinegar Used Concentration of NaOH Run 3 0.100 M Initial Buret reading 0.100 M Final Buret reading 19.68 m Volume of NaOH Used 0.01sas L (Final Buret reading - 1.18.25 Initial Buret reading) 7 2.00 mL 0.100 M L 1 19.68 ml 107.69 mil 360.78 m 2 . Scom 10.017 I L 10.016872 MolML 1 16.87 ML Calculations: 1. Calculate the number moles of...
question 1
Divool Laboratory Report Titration Name maura alarenga Run 1 Run 2 Run 3 Volume of Vinegar Used 2.00 mL oor meerlac | Concentration of NaOH 0.100 M 0.100 M 0.100 M Initial Buret reading 1.43mc 19.68 ml 107.69 m2 Final Buret reading 19.68 m 36.78m lau. som Volume of NaOH Used $.isas L 10.017 0.016872 (Final Buret reading - 8.25 m 17 olme lah 16.87 Initial Buret reading) 1 AL Calculations: 1. Calculate the number moles of base...
question 4
Laboratory Report Titration Run 1 Run 3 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.49 m Final Buret reading 19.68 m Volume of NaOH Used .01sasl (Final Buret reading - 1.18.a Initial Buret reading) Name maura awarenes Run 2 dac 0.220 0.100 M 0.100 M 19.68 ml €7.6mu 360.78 m 10.017 0.01€ 872 117 .me com 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each...
question 6
UUTUUDIY Report Titration Run 1 Run 3 Name Laura A cense Run 2 Volume of Vinegar Used o radac Concentration of NaOH 0.100 M 0.100 M 0.100 M 1.45 mL 1 1 19.68 ml 107.69 m2 Final Buret reading 19.68 m 36.78me lauo some Volume of NaOH Used 6.01sas 0.01710 0,ole 871 (Final Buret reading - 18.a I rolML 18h 16.87 Initial Buret reading) Calculations: 1. Calculate the number moles of base required to reach the endpoint for...
question 5
Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.43 me Final Buret reading - 19.68 m Volume of NaOH Used 0.01sas (Final Buret reading - 1.18.25 Initial Buret reading) to Run 3 Dodac opet 0.100 M 0.100 M 119.68ml 107.69mil 36.78me. lau. Some 0.0171 0.016872 Boh 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each run....
WIJNLIUH Compartir Ventana Ayuda Vinegar Lab Report a página Figura Multimedia Comentario Insertar Tabla Gráfica Texto Laboratory Report -Titration of Vinegar Type Name Here: Go Colaborar Run 1 Run 2 Run 3 2.00 mL 2.00 mL 0.100 M 0.100 M Volume of Vinegar Used Concentration of NaOH Initial Buret reading Final Buret reading Volume of NaOH Used (Final Buret reading - Initial Buret reading) 2.00 mL 0.100 M 1.180 mL 0.05 ml 16.04 ml 0.25 ml 16.92 mL 17.38 ml...
Quantitative Analysis of Vinegar via Titration
Lab Team Members Quantitative Analysis of Vinegar via Titration Report Sheet 1 Part A: Standardizing a Dilute Sodium Hydroxide, NaOH(aq). Solution KHC,H,O,(aq) + NaOH(aq) + H2O(1) + KNaC,H,O,(aq) 204.22 g/mol Trial 1 Trial 2 Trial 3 10.33919 0.36769 0.35989 moles of KHP, mol moles of NaOH, mol initial buret reading, ml 4.00 ml 20.10 mi 30.10 m final buret reading, ml 19.30 ml 35.60m145.10 ml volume of NaOH, ml. volume of NaOH, LL [NaOH],...
Sample 1 .674a Sample 3 0.00 -63619_573989 Sample 2 Mass of KHP taken Initial NaOH buret reading c om m e Final NaOH buret reading 33. ML 32.30ml Volume of NaOH used 33 mL 32.3mL Moles of KHP present 003_ moles_003 mole s kup Molarity of NaOH solution 10 M Mean molarity of NaOH solution and average deviation 0 04 M اور * 5% vinesar Sample 2 WHO Analysis of Vinegar Solution (Part 4a) Identification number (or brand) of vinegar...
fill in 5-9
A. Preparation of Vinegar Sample Brand of vinegar Trial 1 Trial 2 1. Volume of vinegar used (mL) 2. Density of vinegar (g/mL) 3. Mass of vinegar used (g) solution - P.V. 5.0 1002 5.01 5.0 1.000 5.01 B. Analysis of Vinegar Sample 1. Buret reading of NaOH, initial (mL) 2. Buret reading of NaOH, final (mL) 3. Volume of NaOH used (mL) 0 0 43.60 46,90 42.60 41.90 1005 4. Molar concentration of NaOH (mol/L) 5....
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