Ans) 1. For Run 1,
Given Volume of NaOH used = 18.25 mL
Also, Concentration of given NaOH = 0.1 M
Similarly, For Run 2,
For Run 3,
question 1 Divool Laboratory Report Titration Name maura alarenga Run 1 Run 2 Run 3 Volume...
question 2 Laboratory Report Titration 1 11FSI Name maura Quarenga Run 1 Run 2 Volume of Vinegar Used Concentration of NaOH Run 3 0.100 M Initial Buret reading 0.100 M Final Buret reading 19.68 m Volume of NaOH Used 0.01sas L (Final Buret reading - 1.18.25 Initial Buret reading) 7 2.00 mL 0.100 M L 1 19.68 ml 107.69 mil 360.78 m 2 . Scom 10.017 I L 10.016872 MolML 1 16.87 ML Calculations: 1. Calculate the number moles of...
question 3 Run 1 Volume of Vinegar Used 2.00 mot Concentration of NaOH Name maura alarener Run 2 Run 3 o odac 0.20 0.100 M [ 19.68 ml 107.69 mil Lalo Scom 0.100 M Initial Buret reading 0.100 M Final Buret reading 19.68 m Volume of NaOH Used .oisas L (Final Buret reading - 11825 Initial Buret reading) 360.78 me o.017 10.016872 TrolML 10h 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for...
question 4 Laboratory Report Titration Run 1 Run 3 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.49 m Final Buret reading 19.68 m Volume of NaOH Used .01sasl (Final Buret reading - 1.18.a Initial Buret reading) Name maura awarenes Run 2 dac 0.220 0.100 M 0.100 M 19.68 ml €7.6mu 360.78 m 10.017 0.01€ 872 117 .me com 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each...
question 6 UUTUUDIY Report Titration Run 1 Run 3 Name Laura A cense Run 2 Volume of Vinegar Used o radac Concentration of NaOH 0.100 M 0.100 M 0.100 M 1.45 mL 1 1 19.68 ml 107.69 m2 Final Buret reading 19.68 m 36.78me lauo some Volume of NaOH Used 6.01sas 0.01710 0,ole 871 (Final Buret reading - 18.a I rolML 18h 16.87 Initial Buret reading) Calculations: 1. Calculate the number moles of base required to reach the endpoint for...
question 5 Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.43 me Final Buret reading - 19.68 m Volume of NaOH Used 0.01sas (Final Buret reading - 1.18.25 Initial Buret reading) to Run 3 Dodac opet 0.100 M 0.100 M 119.68ml 107.69mil 36.78me. lau. Some 0.0171 0.016872 Boh 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each run....
WIJNLIUH Compartir Ventana Ayuda Vinegar Lab Report a página Figura Multimedia Comentario Insertar Tabla Gráfica Texto Laboratory Report -Titration of Vinegar Type Name Here: Go Colaborar Run 1 Run 2 Run 3 2.00 mL 2.00 mL 0.100 M 0.100 M Volume of Vinegar Used Concentration of NaOH Initial Buret reading Final Buret reading Volume of NaOH Used (Final Buret reading - Initial Buret reading) 2.00 mL 0.100 M 1.180 mL 0.05 ml 16.04 ml 0.25 ml 16.92 mL 17.38 ml...
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used in each trial = 0.20M 3. Volume of NaOH used in trail#1 (Final – Initial buret reading) = __17.80______ mL 4. Volume of NaOH used in trail#2 (Final – Initial buret reading) = ___18.20_____ mL 5. Average Volume of NaOH used = (#3 + #4) / 2 = ___18______ mL 6. Calculate Molarity of Acetic acid in vinegar = _________ M ?????? (molarity of...
titration lab report additional images of lab report QUESTIONS 1. A student masse 0878 of an unknown acid follows the titration procedure required to reach the endpoint on a 10.0 ml Calculate the molar mass of the acid. masses out 0.878 of die in 100 ml volume and titration procedure of Partsherds th the average volume of Non to reach the endpoint on 100 ml aliquot of the acid solution is 18.3 m . 2. In the vinegar titrations (Part...
Lab Report: Titration of Vinegar Experimental Data Trial 1 Trial 2 Initial Buret Reading Trial 3 OML OML OML Final Buret Reading 40 6 ML 40-3 ML 41-7 ML Volume of NaOH used 40.0ML 4 7 40.3 ML Molarity of NaOH used Volume of vinegar used 5ML SML 5ML Data Analysis 1. Write the balanced equation for the neutralization reaction between aqueous sodium hydroxide and acetic acid. The Molarity of Acetic Acid in Vinegar Trial 1 Trial 2 Trial 3...
Quantitative Analysis of Vinegar via Titration Lab Team Members Quantitative Analysis of Vinegar via Titration Report Sheet 1 Part A: Standardizing a Dilute Sodium Hydroxide, NaOH(aq). Solution KHC,H,O,(aq) + NaOH(aq) + H2O(1) + KNaC,H,O,(aq) 204.22 g/mol Trial 1 Trial 2 Trial 3 10.33919 0.36769 0.35989 moles of KHP, mol moles of NaOH, mol initial buret reading, ml 4.00 ml 20.10 mi 30.10 m final buret reading, ml 19.30 ml 35.60m145.10 ml volume of NaOH, ml. volume of NaOH, LL [NaOH],...