Question

Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.43 me Final Buret reading - 19.68 m Volume of NaOH Used 0.01sas (Final Buret reading - 1.18.25 Initial Buret reading) to Run 3 Dodac opet 0.100 M 0.100 M 119.68ml 107.69mil 36.78me. lau. Some 0.0171 0.016872 Boh 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each run. 2. Calculate the number of moles of acid in each sample. 3. Using your answer to calculation 2, calculate the molarity of the vinegar sample for each run. 4. Calculate the average molarity of the vinegar. 5. The true concentration of the vinegar is 5.00g/100mL of vinegar. Calculate the true molarity of the vinegar. . 5

question 5

Answer 1

Solution 5 Concentration of the vinegar = 5.00g 25.00g x 10 Too ml 100 ml x 10 = 50.00g - 50.00g Tooo mi I The chemical formule of Vinegar a C₂H4O2 molar mals of vinegar = 2x12 + 4x I +2x16 260 g/mol We know that No. of moles = given mass Molarmals Since giren mass of vinegar per liter = 50.og .: No. of moles of vinegar a so.og = 0.883 mol. 60 gimol .: molarity of vinegar i = 0.833 mol 7.00 20.83m m (Aus. This true molarity of vinegar = 0.83 m