Answer:
The relationship between K and ∆rG is
∆rG=-RT lnK.
Where R=gas constant=8.314 J/mol.K. and T=temperature.
Given reaction is
CO(g) + 2H2(g) <------> CH3OH(g) K=2.18x10^2
And temperature, T=340 K.
Therefore ∆rG=- RT lnK
∆rG=-(8.314 J/mol.K x 340 K) ln(2.18x10^2)
∆rG=15220.675 J/mol = 15.22 kJ/mol.
Since 1 kJ=1000 J
∆rG ~ 15.2 kJ/mol. (Three significant figures)
Please let me know if you have any doubt. Thanks.
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