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Consider this reaction: standard conditions CO(g) +2 H2(9)CH,OH(g) K-2.18 x 102 at 340 K Express your answer using three sign
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Answer #1

Answer:

The relationship between K and ∆rG is

∆rG=-RT lnK.

Where R=gas constant=8.314 J/mol.K. and T=temperature.

Given reaction is

CO(g) + 2H2(g) <------> CH3OH(g) K=2.18x10^2

And temperature, T=340 K.

Therefore ∆rG=- RT lnK

∆rG=-(8.314 J/mol.K x 340 K) ln(2.18x10^2)

∆rG=15220.675 J/mol = 15.22 kJ/mol.

Since 1 kJ=1000 J

∆rG ~ 15.2 kJ/mol. (Three significant figures)

Please let me know if you have any doubt. Thanks.

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