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Consider the reaction: H2(g) +12(9) =2HI(9) A reaction mixture in a 3.60 -L flask at 500 K initially contains 0.375 g H2 and

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The objective is to calculate the equilibrium constant to the following data. Ang Given that, 0.375g H₂ + 17.919 Iz. molar maat equilibrium mass of HI = 17.76 g. molar mass of HI = 127.9 g/mol. moles of HI = 17.26 -0.1388 moles. 127.9 0.1388 -0.0385

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