23. The rate constant for a particular reaction is 2.7 x 10-2 s at 25°C and...

Question

Question

Answer 1

Answer #1

Given:

T1 = 25 oC

=(25+273)K

= 298 K

T2 = 75 oC

=(75+273)K

= 348 K

K1 = 2.7*10^-2 s-1

K2 = 6.2*10^-2 s-1

use:

ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)

ln(6.2*10^-2/2.7*10^-2) = ( Ea/8.314)*(1/298 - 1/348)

0.8313 = (Ea/8.314)*(4.821*10^-4)

Ea = 14335 J/mol

Ea = 14.3348 KJ/mol

Answer: 14.33 KJ/mol

Answer 2

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