Question

suppose a certain species of awns between 1 and 5 months old have a body weight that is approximately normally distributed with mean μ = 28.6 kilograms and standard deviation σ. 3.7 kilograms. Let x be the weight of a fawn in kilograms. Convert the following : interval to a x interval. 2.7 <z Select one: a. x< 18.61 b. x>18.61 c, x >-38.59 . d. x < 38.59 e. x>38.59

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Answer #1

Answer

We have mean = 28.6, standard deviation = 3.7 and z value = 2.7

z value is less than 2.7

we know the formula z = (x-mu)/sigma

setting given values, we get

2.7 < (r 28.6)/3.7

multiplying both sides by 3.7, we get

2.7 3.7< (x - 28.6)

9.99 < (x-28.6)

adding 28.6 on each side, we get

(9.99 + 28.6) < -28.6 28.6)

we get

38,59く!

so, we can write it as T38.59

option e is correct answer

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