Question

Points out of 4.00 P Flag question a certain species of fawns between I and 5 months old have a body weight that is approximately normally distributed with mean -286 kilograms and standard deviation ơ-3.7 kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to ax interval 2.7<z Select one: o a. x< 18.61 O b. x>18.61 O c. x>-38.59 d. x>38.59 ● e. x < 38.59

Answer 1

Given that, mean $(\mu)$ = 28.6 and

standard deviation $(\sigma)$ = 3.7

Given that, 2.7 < z

We know,

$Z =\frac { X - \mu}{\sigma}$

$=> X = Z \sigma &plus; \mu$

$=> X = (2.7 * 3.7)&plus; 28.6$

$=> X = 9.99 &plus; 28.6$

$=> X = 38.59$

Therefore,

2.7 < z

=> 38.59 < x

=> x > 38.59

Answer: d) x > 38.59