From the balanced equation we can say that
2 mole of butane produces 8 mole of CO2 so
2.76 mole of butane will produce
= 2.76 mole of butane *(8 mole of CO2 / 2 mole of butane)
= 11.04 mole of CO2
mass of 1 mole of CO2 = 44.01 g so
the mass of 11.04 mole of CO2 = 486 g
Therefore, the mass of CO2 produced would be 486 g
Question 10 of 14 How many grams of CO2 can be produced from the combustion of...
According to the balanced equation below, when 4 mol of butane (C4H10) undergo combustion, how many moles of CO2 are produced? 2 C4H10() + 13 O2(g) → 8 CO2(g) + 10 H2O(9) O2 04 08 16 32
1. [12.7 g C4H10] Butane, C4H10, is a common fuel. How many grams of butane can be burned by 45.4 grams of oxygen? 2 C4H10 + 13 O2 ---> 8 CO2 + 10 H2O 2. [350. g NH4NO3] The fertilizer ammonium nitrate (NH4NO3) can be made by direct combination of ammonia with nitric acid: NH3 + HNO3 ----> NH4NO3 If 74.4 grams of ammonia (NH3) is reacted with nitric acid, how many grams of ammonium nitrate can be produced?...
5. How many grams of CO2 will be produced from the combustion of 28.06 g of C4H10 in the presence of 16.0 g of O, if the reaction yield is 95.0%? C4H10 + O2 → CO2 + H2O a) 13.5 g b) 12.9 g c) 2.69 g d) 1.95 g
Using the balanced equation, calculate how many grams of CO2 are produced from the combustion of 30.06 g of C2H6 with 128.00 g of oxygen gas. 2 C2H6 (g) + 7 O2 (g) -> 4 CO2 (g) + 6 H2O (g) a) 176.04 g b) 88.02 g c) 44.01 g d) 100.6 g
Calculate how many grams of butane (C4H10) form when 1.11 g of O2 reacts completely given the following equation: 2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)
can you do the 7 and 9 ? can you also show and explain me step by step? D. 49.6 kJ E. 57.3 kJ 7. Butane (C4H10) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. Given AH° [C4H10(g)] = -124.7 kJ/mol, AH° [CO2(g)] = -393.5 kJ/mol, AH [H2O(g)] = -241.8 kJ/mol, how much energy is released (kJ) when 8.30 g of butane is burned? Combustion of butane: 2 CH2(g) + 13 O2(g) → 8 CO2(g) +...
2 KCIO, 2 KCI + 30, 10. How many grams of O, will be formed from 3.76 grams of KCIO. 3.76g KCIO. I mol KCIO, mol - 80 122.55 g KCIO,_mol KCIO, _mol O, 11. How many grams of KCIO, are needed to make 300 grams of KCI? 30.0 g KCI m ol KCI mol KCIO, _ KCIO, — g KCI - mol KCI Lmol KCIO, 12. How many grams of KCl will be formed from 2.73 g of KCIO,?...
1) The combustion of a sample of butane, C.H(lighter fluid), produced 2.46 grams of water. 2 C4H10 + 1302 -------> 8CO2 + 10H20 (a) How many moles of water formed? (b) How many moles of butane burned? (c) How many grams of butane burned? (d) How much oxygen was used up in moles? (e) How much oxygen was used up in grams? 2) Using the following equation: 2 NaOH + H2SO4 → 2 H2O + Na2SO4 How many grams of...
2) Balance C4H10 + O2 → CO2 + H2O & solve: a) If 7.54 mol of CO2 are produced, how many moles of O2 reacted? b)If 9.75 kg of H2O are produced, how many moles of C4H10 reacted? c) If 3.4500 moles of O2 react, how many grams of CO2 are produced? d)If 520.30 grams of C4H10 react, how many mg of H2O are produced? e) If 4.28 mol H2O are produced, how many molecules of O2 reacted?
10. (a) Determine the mass of calcium oxide (CaO, lime) that can possibly be produced by heating 44.6 g of calcium carbonate (CaCO). The balanced equation for this reaction is shown in Equation 8 heat CaO(s) +CO2 (g) CaCOs(s) (Eq. 8) (b) Determine the mass of CO2 that would be produced by the reaction described in (a). 11. Joseph Priestley's study of the decomposition of mercury(ID oxide (HgO) with heat led to the discovery of O2. The balanced equation for...