Question

What’s the answer?

Suppose in the figure blow that +1.15% 103 J of work is done by the force F (magnitude 30.0 N) in moving the suitcase a distance of 58.0 m. At what angle θ, counterclockwise from the x-axis, is the force oriented with respect to the ground? Fcose Read the eBook Section 6.1 Work Done by a Constant Force

Answer 1

Horizontal component of the force, Fx = F*cos$\Theta$

Distance traveled by the person, s = 58.0 m

Work done, W = 1.15 x 10^3 J

Now, as we now that -

Work done = Force in the direction of movement x Displacement

=> W = Fx * s

=> 1.15 x 10^3 = F*cos$\Theta$ * 58.0

=> F*cos$\Theta$ = (1.15 x 10^3) / 58 = 19.825

=> cos$\Theta$ = 19.825/F = 19.825 / 30.0 = 0.661

=> $\Theta$ = cos^-1(0.661) = 48.6 deg. (Answer)