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(a) How much work must be done to raise a 2.00 kg mass a vertical distance of 1.00 m by pushing it up a frictionless inclined
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Answer #1

6)The work done will be equal to the potential energy

PE = m g h

W = 2 x 9.8 x 1 = 19.6 J

Hence, W = 19.6 J

b)W = F d

d = 1/sin30 = 2 m

19.6 = F x 2 => F = 19.6/2

F = 9.8 N

c)d = 1/sin30 = 2 m

Hence, d = 2 m

d)M = force produced/force applied

M = 1

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