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A block of weight w = 35.0 N sits on a frictionless inclined plane, which makes...

A block of weight w = 35.0 N sits on a frictionless inclined plane, which makes an angle ? = 24.0 ? with respect to the horizontal, as shown in the figure. (Figure 1)A force of magnitude F = 14.2 N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed.

What is WF, the work done on the block by the applied force F? as the block moves a distance L = 4.90 m up the incline?

What is WN, the work done on the block by the normal force as the block moves a distance L = 4.90 m up the inclined plane?

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Answer #1

Constant speed means no change in K which means the net Work is zero

Work done by applied force:

W_F = F*d = 14.2N*4.9 M = 69.58J

Work done by normal force:

W_N = 0 J (force is perpendicular to the motion)

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