Question

12 of13 > Constants - Part A A block of mass 1.00 kg sits on an inc ined plane as shown (Figure 1)A torce of magnitude 400 Ns pulting the block up the incine The coefficient of knetic fretion between the plane and the block is What is the total work Wie done on the block by the force of friction as the block moves a distance 5 00 in up the incine? Express the work done by friction numerically, in Joules View Available Hints Figure 1of2 Win Subma Part B

Answer 1

you will have to give the values of friction and angle

Minimum force required to move up the inclined plane is F_1 = mg (sin theta + mu cos theta) w = F_1 middot x take x = 5.0 F_1 = 40 N w = 200 J w = F_1 middot L = mg (sin theta + mu cos theta) times L Therefore m = 100 kg g = 10 = L (sin theta + mu cos theta) times 10^3 you will have to give the numerical values of theta & mu frictional force F_fric = mu N = mu mg cos theta F_fric = mu cos theta times 10^3 w_fric = mu cos theta middot (4 times 10^3) for downward motion w = -w_fric