(6) Mass of the aluminium piece, m = 5.4 g = 5.4 x 10^-3 kg
Volume of the aluminium piece, v = length x breadth x thickness
= 0.02 x 0.02 x 0.005 m^3 = 0.000002 m^3
Hence, density of aluminium piece, = m/v = (5.4 x 10^-3) / 0.000002 = 2700 kg/m^3
(7) The ball is thrown upward with a velocity, v = 8 m/s
Height of the building, h = -36 m (we have taken negative sign because we are taking the point of throwing as origin)
Use the expression -
h = v*t + (1/2)*g*t^2
=> -36 = 8t + 0.5*(-9.8)*t^2
=> 4.9t^2 - 8t - 36 = 0
=> t = [8 + sqrt(8^2 + 4*4.9*36)] / (2*4.9)
= [8 + 27.7] / 9.8 = 3.64 s (Answer)
Other value of 't' can be discarded as it will be negative.
(8) At, t = 3 s
v(3) = (3^2 - 2*3)m/s i + (6*3 + 2) m/s j = 3 m/s i + 20 m/s j
So, magnitude of velocity, |v| = sqrt[3^2 + 20^2] = 20.22 m/s (Answer)
a) grams, c) meters, seconds, kilograms 6. A square piece of aluminium with as mass of...
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