An object thrown vertically upward from the surface of a celestial body at a velocity of 24 m/s reaches a height of s = -0.6t2 + 24t meters in t seconds.
a. Determine the velocity v of the object after t seconds.
b. When does the object reach its highest point?
c. What is the height of the object at the highest point?
d. When does the object strike the ground?
e. With what velocity does the object strike the ground?
f. On what intervals is the speed increasing?
An object thrown vertically upward from the surface of a celestial body at a velocity of 24 m/s reaches a height of s = -0.6t2 + 24t meters in t seconds.
3.6.25 Question Help An object thrown vertically upward from the surface of a celestial body at a velocity of 24 m/s reaches a height of su-0.612 + 24 meters in t seconds. a. Determine the velocity v of the object after t seconds. b. When does the object reach its highest point? c. What is the height of the object at the highest point? d. When does the object strike the ground? e. With what velocity does the object strike...
A rock thrown vertically upward from the surface of the moon at a velocity of24 m/sec reaches a height of s=24t-0.8t^2 meters in t seconds.a) Find the rock’s acceleration and velocity at time t.b) How long does it take the rock to reach its highest point?c) How high does the rock go?d) How long does it take the rock to reach half its maximum height?e) How long is the rock aloft?
An object is thrown vertically and has an upward velocity of 25 m/s when it reaches one fourth of its maximum height above its launch point. What is the initial (launch) speed of the object?
An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its launch point. What is the initial (launch) speed of the object?
if an object is thrown vertically upward with an initial
velocity of v, from an original position of s, the height h at any
time t is given by:
h = -16t^2 + vt + s
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by h16t2 +vt+s (where h and s are in ft, t is in seconds and v...
If a stone is thrown vertically upward from the surface of the moon with a velocity of 6 m/s, its height (in meters) after t seconds is h = 6t - 0.83t2. (Round the answers to two decimal places.) a. What is the velocity of the stone after 3 s? b. What is the velocity of the stone after it has risen 8 m?
An object is thrown upward from 1 m above the ground. It travels vertically up, reaches a maximum height of 2.5 m above ground, falls back down, and is caught at exactly the same position it was thrown 1 s after it was thrown. What was the average velocity of the object? Click the answer you think is right 1.5 m/s 0 m/s 3 m/s
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
If a rock is thrown upward on the planet Mars with a velocity of 17 m/s, its height (in meters) after t seconds is given by H = 17t - 1.86t^2.(a) Find the velocity of the rock after two seconds.(b) Find the velocity of the rock when t = a.(c) When will the rock hit the surface? (Round your answer to one decimal place.)(d) With what velocity will the rock hit the surface?
A blue ball is thrown upward with an initial speed of 22.8 m/s, from a height of 0.6 meters above the ground. 2.8 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 7.7 m/s from a height of 28.2 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2. ) What is the speed of the...