Question

if an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by:

h = -16t^2 + vt + s

If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by h16t2 +vt+s (where h and s are in ft, t is in seconds and v is in ft/sec) Solve for t when the object hits the ground (when h-o) t= blank 1 ± 'vi ank 2-4(blank 2(-16) Fill in the blanks of the quadratic formula. Enter: blank 1, blank 2, blank 3 (separated by commas)

Answer 1