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If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2

If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2. Find the number of seconds the object is in the air before it hits the ground.
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If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2. Find the number of seconds the object is in the air before it hits the ground. --------------- It's at ground level when h = 0. h = 64t - 16t^2 = 0 t = 0 seconds t = 4 seconds ------------- It's at ground level at 0 seconds, and returns to ground level after 4 seconds.
answered by: 4th grade
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If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2
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