If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2
If an object is projected upward with an initial velocity of 48 ft pe second from a height h of 160 ft, then its height t second after it is projected is defined by the equation h= -16t 2 + 48t + 160. How many seconds after it is projected will it hit the ground?
if an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h = -16t^2 + vt + s If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by h16t2 +vt+s (where h and s are in ft, t is in seconds and v...
At moment of time t=0 a projectile is fired directly upward with an initial velocity 192 ft/sec, and initial height 200 ft. Find: a)velocity and acceleration after t seconds, (b) velocity when projectile hits the ground, (c) time of travel from the highest point to the ground. Equation of motion is h"= -32, where h(t) is the height of projectile at moment t.
An object is thrown upward from a height of 6 feet at a velocity of 64 feet per second. The height of the object h is a function of time t. h(t) = -16+2 +64t + 6 At what time the function h will reach its maximum value.
If a ball is thrown directly upward with a velocity of 80ft/s, its height (in feet) after t seconds is given by y=80t-16t^2. What is the maximum height attained by the ball?
The height h (in feet) of an object falling from a tall building is given by the function h(t) 400 16, where t is the time elapsed in seconds (a) After how many seconds does the object strike the ground? (b) What is the average velocity of the object from t- o until it hits the ground? (c) Find the instantaneous velocity of the object after I second ft/sec Find the instantaneous velocity of the object after 2 seconds. ft/sec...
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t-16t^2 .After how long will it reach its maximum height? Do not round your answer.
show work 4. Suppose a stone is launched vertically upward with initial velocity 32 ft/sec from a height of 48 ft above ground. After t seconds its height is given by s(t) = -16t2 + 32t + 48 At the time when the stone hits the ground it is moving with a speed of A. 32 ft/s B. 24 ft/s C. 64 ft/s D. 48 ft/s E. 96 ft/s
A rocket is fired upward from some initial distance above the ground. Its height in feet, h,above the ground, t seconds after it is fired, is given by h= -16t^2+32t+3584. What is the rocket's maximum height? ___ ft How long does it take for the rocket to reach its maximum height? t= ___sec After it is fired, the rocket reaches the ground at t= ___ sec.
5. If a ball is thrown directly upward with a velocity of 46 ft/s, its height (in feet) aftert seconds is given by y = 46t - 16t? What is the maximum height attained by the ball? Round your answer to the nearest whole number.