If a ball is thrown directly upward with a velocity of 80ft/s, its height (in feet) after t seconds is given by y=80t-16t^2. What is the maximum height attained by the ball?
If a ball is thrown directly upward with a velocity of 80ft/s, its height (in feet) after t seconds is given by y=80t-16t^2
5. If a ball is thrown directly upward with a velocity of 46 ft/s, its height (in feet) aftert seconds is given by y = 46t - 16t? What is the maximum height attained by the ball? Round your answer to the nearest whole number.
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t-16t^2 .After how long will it reach its maximum height? Do not round your answer.
A ball is thrown vertically upward. After seconds, its height h (in feet) is given by the function h(G)-92r-16f. What is the maximum height that the ball will reach? Do not round your answer
(6) A ball is thrown directly upward from a height of 11 feet with an initial velocity of 192 ft/s.The function (1) =-161° +1921 +11 gives the height of the ball in feet, 7 seconds after it has been thrown. Determine the time at which the ball reaches the maximum height and find the maximum height
If a ball is thrown upward at 96 feet per second from a height of 12 feet, the height of the ball can be modeled by S- 12+96t seconds after the ball is thrown. How long after the ball is thrown is the height 152 feet? 16t feet, where t is the number of t takes seconds for the ball to reach th (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) e height...
If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2. Find the number of seconds the object is in the air before it hits the ground.
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
a ball is thrown upward at 64 feet per second from the top of an 80 feet high building. The height of the ball can be modeled by S(t) = -16t^2 + 64t + 80(feet), where t is the number of seconds after the ball is thrown. describe the graph model
If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2. Find the average velocity for the time period begining when t=1 and lasting(i) 01 seconds: (ii) 001 seconds:(iii) 0001 seconds:Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1.
Math 121 College Algebra Test F 7. A ball is thrown directly upward from a height of 6 ft with an initial velocity of 20 fu/sec. a) Express the height s of the ball, in feet, seconds after it has been thrown. b) Determine the time at which the ball reaches its maximum height. Round the answer to two decimals c) Find the maximum height of the ball. Round the answer to two decimals