Kindly go through the solution and let me know in case of any doubt
or further clarification in the comment box.
Thanks for the question :)
And your upvote will be really appreciable ;)
If a ball is thrown upward at 96 feet per second from a height of 12...
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
a ball is thrown upward at 64 feet per second from the top of an 80 feet high building. The height of the ball can be modeled by S(t) = -16t^2 + 64t + 80(feet), where t is the number of seconds after the ball is thrown. describe the graph model
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t-16t^2 .After how long will it reach its maximum height? Do not round your answer.
An object is thrown upward at a speed of 161 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h(t) = 16t2 + 161t + 8 When will the height be 67 feet? (Write both results, using a comma between). Round answers to the nearest hundredth. Select an answer Select an answer ict reach the ground? seconds 1 answer...
An object is thrown upward at a speed of 182 feet per second by a machine from a height of 14 feet off the ground. The height hh of the object after tt seconds can be found using the equation h=−16t^2+182t+14h=- When will the height be 515 feet? Round to two place When will the object reach the ground? Round to two places. USE EXCEL SOLVER!!
If a ball is thrown directly upward with a velocity of 80ft/s, its height (in feet) after t seconds is given by y=80t-16t^2. What is the maximum height attained by the ball?
An object is thrown upward at a speed of 194 feet per second by a machine from a height of 6 feet off the ground. The height hh of the object after tt seconds can be found using the equation h(t)=−16t2+194t+6h(t)=-16t2+194t+6 When will the height be 522 feet? (Write both results, using a comma between). Round answers to the nearest hundredth. When will the object reach the ground?
If a ball is thrown upward at 49 meters per second from the top of a building that is 35 meters high, the height of the ball can be modeled by S = 35 + 49 - 4.912, where t is the number of seconds after the ball is thrown. Answer parts a through c a. Find the t-coordinate and S-coordinate of the vertex of the graph of this quadratic function. The t-coordinate of the vertex of the graph of...
A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s=48-16t2. (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 32 feet above the ground?
A ball is thrown vertically upward. After seconds, its height h (in feet) is given by the function h(G)-92r-16f. What is the maximum height that the ball will reach? Do not round your answer