A ball is thrown vertically upward with an initial velocity of 48 feet per second.
A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s=48-16t2.
(a) At what time t will the ball strike the ground?
(b) For what time t is the ball more than 32 feet above the ground?
Homework Answers
Hence answer a) is 3 second
and answer b) is 1 second.Add Answer to:
A ball is thrown vertically upward with an initial velocity of 48 feet per second.
A ball is thrown vertically upward with an initial velocity of 96 feet per second
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
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An object is propelled upward at an initial velocity of 32 feet per second at a. initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -16t2 + 326 +48 for Osts 3 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 0 sec and t = 2 sec A) O feet per second B) 24 feet per second C) 12 feet per...
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show clear work plz A ball is thrown upward from a height of 1000 feet above...
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A ball is thrown upward from a height of 1000 feet above the ground, with an initial velocity of 80 feet per second. From physics it is known that the acceleration at time t is a(t) = -32 feet per second squared. Use antiderivatives to find s(t), the function giving the height of the ball at timet.
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An object is propelled upward at an initial velocity of 32 feet per second at a. initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -16t2 + 326 +48 for Osts 3 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 0 sec and t = 2 sec A) O feet per second B) 24 feet per second C) 12 feet per...
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An object is thrown upward at a speed of 161 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h(t) = 16t2 + 161t + 8 When will the height be 67 feet? (Write both results, using a comma between). Round answers to the nearest hundredth. Select an answer Select an answer ict reach the ground? seconds 1 answer...
show clear work plz
A ball is thrown upward from a height of 1000 feet above the ground, with an initial velocity of 80 feet per second. From physics it is known that the acceleration at time t is a(t) = -32 feet per second squared. Use antiderivatives to find s(t), the function giving the height of the ball at timet.
show work
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