An object is propelled upward at an initial velocity of 32 feet per second at an...
An object is propelled upward at an initial velocity of 32 feet per second at a. initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -16t2 + 326 +48 for Osts 3 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 0 sec and t = 2 sec A) O feet per second B) 24 feet per second C) 12 feet per...
A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s=48-16t2. (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 32 feet above the ground?
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
12. Use the fact that acceleration is - 32 feet per second per second as the acceleration due to gravity. A ball is thrown vertically upward from the ground with an initial velocity of 56 feet per second. For how many seconds will the ball be thrown upward? Recall v(t) = a(t)- dt and s(t) = f(t)-dt
If an object is thrown with a velocity of v feet per second at an angle of θ with the horizontal, then its flight can be modeled by, x = (v cos θ ) t and y = v (sin θ ) t - 16 t2 + h where t is in seconds and h is the object's initial height in feet above the ground. x is the horizontal position and y is the vertical position, and - 16 t2...
A model rocket is launches upward with an initial velocity of 160 feet per second. The height, in feet, of the rocket t seconds after the launch is given by h=-16t^2+160t. How many seconds after the launch will the rocket be 290 feet above the ground? Round to the nearest tenth of a second.
show work 4. Suppose a stone is launched vertically upward with initial velocity 32 ft/sec from a height of 48 ft above ground. After t seconds its height is given by s(t) = -16t2 + 32t + 48 At the time when the stone hits the ground it is moving with a speed of A. 32 ft/s B. 24 ft/s C. 64 ft/s D. 48 ft/s E. 96 ft/s
An object is thrown upward at a speed of 161 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h(t) = 16t2 + 161t + 8 When will the height be 67 feet? (Write both results, using a comma between). Round answers to the nearest hundredth. Select an answer Select an answer ict reach the ground? seconds 1 answer...
3. A baseball is projected upward form the top of 448 foot tall bulding with an initial velocity of 48 feet per second. The distance s of the baseball from the ground at any time t, in seconds, is glven by the equation s-16r2 +48t+448 How long will it take the ball to hit the ground? a. b. How high will the ball be in 6 seconds? When will the ball be 448 feet in the air? c. d. If...
10) An object is propelled upward at an angle e, 45° << 90°, to the horizontal with an initial velocity of vo feet per second from the base of a plane that makes an angle of 45° with the horizontal. If air resistance is ignored, th distance R that it travels up the inclined plane is given by the function vo22 R(O) = [sin(20) - COS(20) - 11. 32 Show that v02/2 R(O) = [sin (cos 0 + sin o)...