A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2
a.) at what time will the ball strike the ground
b.) for what time t is the ball more than 128 feet above the ground?
c.) when will the ball reach its highest peak? how high is it above the ground?
A ball is thrown vertically upward with an initial velocity of 96 feet per second
A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s=48-16t2. (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 32 feet above the ground?
If a ball is thrown upward at 96 feet per second from a height of 12 feet, the height of the ball can be modeled by S- 12+96t seconds after the ball is thrown. How long after the ball is thrown is the height 152 feet? 16t feet, where t is the number of t takes seconds for the ball to reach th (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) e height...
a ball is thrown upward at 64 feet per second from the top of an 80 feet high building. The height of the ball can be modeled by S(t) = -16t^2 + 64t + 80(feet), where t is the number of seconds after the ball is thrown. describe the graph model
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t-16t^2 .After how long will it reach its maximum height? Do not round your answer.
if an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h = -16t^2 + vt + s If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by h16t2 +vt+s (where h and s are in ft, t is in seconds and v...
A model rocket is launches upward with an initial velocity of 160 feet per second. The height, in feet, of the rocket t seconds after the launch is given by h=-16t^2+160t. How many seconds after the launch will the rocket be 290 feet above the ground? Round to the nearest tenth of a second.
6. Thorough algebraic work to support the results is required for credit. A ball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 43 feet per second. The distance, s (in feet), of the ball from the ground after t seconds is given by the function: als s(t) = 96 + 43t - 16t2 luty 1919 ini a. How long does it take for the ball to reach its ! highest...
Fill in the Blanks A golf ball is projected upward from ground level at an initial velocity of 112 ft/sec. The height of a projectile can be modeled by s(t) = -16t+ vot + So, where t is time in seconds, So is the initial height in feet, and Vo is the initial velocity in ft/sec. a. How high will the ball be after 2 sec? O feet b. What is the maximum height the ball reaches? O feet c....
12. Use the fact that acceleration is - 32 feet per second per second as the acceleration due to gravity. A ball is thrown vertically upward from the ground with an initial velocity of 56 feet per second. For how many seconds will the ball be thrown upward? Recall v(t) = a(t)- dt and s(t) = f(t)-dt
An object is propelled upward at an initial velocity of 32 feet per second at a. initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -16t2 + 326 +48 for Osts 3 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 0 sec and t = 2 sec A) O feet per second B) 24 feet per second C) 12 feet per...