Question

6. Thorough algebraic work to support the results is required for credit. A ball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 43 feet per second. The distance, s (in feet), of the ball from the ground after t seconds is given by the function: als s(t) = 96 + 43t - 16t2 luty 1919 ini a. How long does it take for the ball to reach its ! highest point? Round to 2 decimal places. San199 shov V OXA 1991- b. What is the maximum height the ball reaches? Round to 2 decimal places.

Answer 1

Given function is S(t)96+43t -16t2^0 Ditsonantiate both side with baapad to t dsit) dt (96+43t -16t) - 43-32t We knod that at the top paint, velocity bal became O dt 43-32t O 32t 43 t43 1 344 34 Comhact upto 2 deeima It takes 34 Sacond to beach its highest paint (A

The ball baoche maumum hoght at t= l 3 4 Secnd. put tha value t cn O :h= 96 A3 X I34 16 ( 34) 124.89 feat 124.89 feet(Ang wen :Maximum height (b9 Here, 80 Can not be addad bocausa given unctia asis G gSund 100