An object is thrown upward at a speed of 182 feet per second by a machine from a height of 14 feet off the ground. The height hh of the object after tt seconds can be found using the equation h=−16t^2+182t+14h=-
When will the height be 515 feet?
Round to two place
When will the object reach the ground?
Round to two places. USE EXCEL SOLVER!!
You can skip the half page of the first pic because I have just checked wether the particle cross the highest point Q or not.
The answers are given in the brackets.
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An object is thrown upward at a speed of 182 feet per second by a machine...
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