7. (a) yi = 6 ft
v0 =20 ft/s
a = - 32.17 ft/s^2
yf - yi = v0 t + a t^2 / 2
h - 6 = (20 t) + (-32.17 t^2 / 2)
h = 6 + 20t - 16 t^2
(B) h will be max when dh/dt = 0
20 - 32 t = 0
t = 0.62 sec
(C) putting value of t,
h = 12.22 ft
Math 121 College Algebra Test F 7. A ball is thrown directly upward from a height...
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