Question

3.6.25 Question Help An object thrown vertically upward from the surface of a celestial body at a velocity of 24 m/s reaches a height of su-0.612 + 24 meters in t seconds. a. Determine the velocity v of the object after t seconds. b. When does the object reach its highest point? c. What is the height of the object at the highest point? d. When does the object strike the ground? e. With what velocity does the object strike the ground? f. On what intervals is the speed increasing? a. The object's velocity after t seconds is vit)-O t

Answer 1

Uo - rumis Sa 14 given inhal veloc velocity S= -0.61² , aut and int seconds Neverly of object (20.66 6t ²+ luf) = 2(-0.6) t + 24 ds ct = d dt = -1.2t plu (b) pelhen velrenty will become 30o Then Object will reach its highest point 2 -1.26 p24 CO 24 ats ts Luo K Es lo second realh at hy west It will take t= 20 second point So to height et S= -0.02) ?724 (20 -0.6 (200) + 24 (2) -ruo tuoo L40 When the a height will pero So 7 -0.6 +² +4 +=0 = (-0.6t+24) t = t-o and 0-6 truar ts 24 < Ito t 0 ( ts it is initial position 4.О. U to al t540 it will will stuck the ground find velouly @ at t-ud U= -1.26724 4 = - x10 + L4 -40424 = -24 0 - negative sign Shew that object coming clown please give thumbs up if it help you" Scanned with CamScanner

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