An object is thrown upward from 1 m above the ground. It travels vertically up, reaches a maximum height of 2.5 m above ground
An object is thrown upward from 1 m above the ground. It travels vertically up, reaches a maximum height of 2.5 m above ground, falls back down, and is caught at exactly the same position it was thrown 1 s after it was thrown. What was the average velocity of the object?
Click the answer you think is right
1.5 m/s
0 m/s
3 m/s
Homework Answers
Average velocity = net displacement / total time taken
Net displacement is zero in this case because object come back at the same position.
So average velocity = 0 / 1 = 0 m/s
Option (B) is correct.
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