Question

An object is thrown upward from 1 m above the ground. It travels vertically up, reaches a maximum height of 2.5 m above ground


An object is thrown upward from 1 m above the ground. It travels vertically up, reaches a maximum height of 2.5 m above ground, falls back down, and is caught at exactly the same position it was thrown 1 s after it was thrown. What was the average velocity of the object? 

Click the answer you think is right 

1.5 m/s 

0 m/s 

3 m/s

3 1
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Answer #1

Average velocity = net displacement / total time taken

Net displacement is zero in this case because object come back at the same position.

So average velocity = 0 / 1 = 0 m/s

Option (B) is correct.

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