Question

A person applies a horizontal force of 200N to a 40kg crate that moves 2m along a 5º incline. Find the work on the crate *9 Y F= 200N 1) By the person 2) By the friction if us = 0.25 3) By gravity 4) Using the work energy theorem find the final speed if the crate starts from rest.

Answer 1

2 metres .ON 4 north Fa 250N dx = 2mall = 0.25 Sine N ass thalsing a personn = F.dx = Fon caso = (F caso) dx = 200 Cars 5°x2 = 398.485 b) w By the friction fri = (fr) x de - lele N) are = Mk ong cas 5 x2 = 0.25*40*9.8 x cos 5 x2 = 195.25 J E) By gravity : W growity = mgh = mgesino = 4089.8 x 2 x sins 568.335 => d) Work done by all forces = oke (Wperson - Wgrow - W en ) = Į muz - meo) 1349 = 1x 40002 gu 126.745 = 2.60 m la

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