A 40 kg crate is pulled 50 m along a horizontal floor by a constant force exerted by a person, Fp = 150 N, which acts as 30 degree angle. The floor is rough and exerts a friction for Ff = 40 N. Determine: a) the work done by each force acting on the crate b) the net work done on the crate
Work done by the force acting on the crate
Wp = Fp.s = Fp*s*cos theta
Wp = 150*50*cos 30 deg = 6495.19 J
B.
work due to normal force
Wn = Fn*s*cos theta
theta = 90 deg
cos 90 = 0
Wn = 0
Wg = Fg*s*cos theta
theta = 90 deg
cos 90 = 0
Wg = 0 J
total work will be
Wt = Wp + Wn + Wg
Wt = 6495.19 J
A 40 kg crate is pulled 50 m along a horizontal floor by a constant force...
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