Given:
Energy of 1 mol = 2.39*10^2 KJ/mol
= 2.39*10^5 J/mol
Find energy of 1 photon first
Energy of 1 photon = energy of 1 mol/Avogadro's number
= 2.39*10^5/(6.022*10^23)
= 3.969*10^-19 J
This is energy of 1 photon
use:
E = h*c/lambda
3.969*10^-19J =(6.626*10^-34 J.s)*(3.0*10^8 m/s)/lambda
lambda = 5.01*10^-7 m
lambda = 501 nm
Answer: 501 nm
The photoelectric work function for barium metal is 239 kilojoules per mole of electrons ejected from...
The maximum wavelength of electromagnetic radiation capable of removing an electron from the surface of a certain metal is 421.2 nm. Use this information to determine the work function for the metal in kJ per mole of electrons ejected.
The minimum frequency of electromagnetic radiation capable of removing an electron from the surface of a certain metal is 7.42x10+14 s-1. Use this information to determine the work function for the metal in kJ per mole of electrons ejected. The minimum frequency of electromagnetic radiation capable of removing an electron from the surface of a certain metal is 7.42x10's. Use this information to determine the work function for the metal in kj per mole of electrons ejected. kJ/mole Check
The photoelectric work function energy for gold metal is 4.82 eV (per electron). What wavelength of radiation must be directed at the surface of gold metal in order to eject electrons electrons having a maximum kinetic energy of 3.20×10 –20 Joules/electron. [Note: The electron volt (eV) is a common energy unit for work function energies. 1 eV = 1.602×10 –19 Joules.] -20 The photoelectric work function energy for gold metal is 4.82 eV (per electron). What wavelength of radiation must...
A photoelectric surface has a work function of 2.10 eV. Calculate the maximum kinetic energy, in eV, of electrons ejected from this surface by electromagnetic radiation of wavelength 356 nm. (Note: h = 6.63x10^-34 C and c = 3.00x10^8 m/s).
The photoelectric work function energy for manganese metal is 3.76 eV (per electron). What wavelength of radiation must be directed at the surface of manganese metal in order to eject electrons electrons having a maximum kinetic energy of 2.00×10 –19 Joules/electron. [Note: The electron volt (eV) is a common energy unit for work function energies. 1 eV = 1.602×10 –19 Joules.] Wavelength (λ) = Answer nm
The photoelectric work function energy for manganese metal is 3.76 eV (per electron). What wavelength of radiation must be directed at the surface of manganese metal in order to eject electrons electrons having a maximum kinetic energy of 2.00×10 –19 Joules/electron. [Note: The electron volt (eV) is a common energy unit for work function energies. 1 eV = 1.602×10 –19 Joules.]
The photoelectric work function energy for manganese metal is 3.76 eV (per electron). What wavelength of radiation must be directed at the surface of manganese metal in order to eject electrons electrons having a maximum kinetic energy of 2.00×10 –19 Joules/electron. [Note: The electron volt (eV) is a common energy unit for work function energies. 1 eV = 1.602×10 –19 Joules.]
Light striking a metal surface causes electrons to be emitted from the metal via the photoelectric effect.In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?Check all that apply.The work function of the metal decreases.The number of electrons...
Photoelectric 1 A Sodium photoelectric surface with a work function of 2.3 eV is illuminated by electromagnetic radiations and emits electrons. The emitted electrons travel towards a negatively charged cathode. For the electrons emitted from the Sodium surface, calculate: - The maximum Kinetic Energy of the electrons Their speed at this maximum Kinetic Energy. Calculate the wavelength of the radiation that is incident on the Sodium surface Calculate the minimum frequency of light that will cause the emission of electrons....
When electromagnetic radiation with a wavelength of 326.0 nm is directed at the surface of a certain metal, electrons are ejected from the surface with a de Broglie wavelength of 9.65 Å. Calculate the work function for the metal in kJ/mole of e ejected. 1 Å (angstrom) = 1x10 meters kJ/mol e Check