Consider the following diagram. The rod of length L is uniformily charged and has a total...

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Consider the following diagram. The rod of length L is uniformily charged and has a total charge Q. What is the expression for the electric field component Ey at point P? Ey ET

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Answer 1

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Electric field due to small element dq 1S 1 dq Lets assume that linear charge density of rod is λ. 1 λάκ dx 1 λάκ

from diagram wve can see that cose- _ using above relations ax (h2 +x2)3/- for solving this integral: , Ltd λ ax 273/2

now substitute tane ах h21+ L+d finally, we get electric field along y- direction - L+ d 4TtEgh

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Consider the following diagram. The rod of length L is uniformily charged and has a total...

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