18. In the hypothetical equilibrium 2AB(g) A2B2(g), K = 250. In a mixture of the two...

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18. In the hypothetical equilibrium 2AB(g) A2B2(g), K = 250. In a mixture of the two gasses, the concentration of A2B2 is 1.5

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Answer 1

Answer #1

Given that the hypothetical equilibrium, 2 AB(g) $\leftrightarrow$ A2B2(g), K =250

The equilibrium constant of the reaction, K = [A2B2]/[AB]²

The equilibrium concentration of A2B2 is 1.5*10^-3 M.

The equilibrium constant of the reaction, K = 1.5*10^-3 /[AB]² = 250

The equilibrium concentration of AB is 2.44*10^-3 M.

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Answer 2

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