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Standard Entropy and Entropy Change of Reactions Using standard entropy values (from the appendices of your text), calculate

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Answer #1

For the first reaction,

dS = dS(HCl)-dS(H+)-dS(Cl-) = 186.8-0-56.5 J/Kmol = 129.5 J/Kmol

For the second reaction,

dS = 2dS(NO)-dS(O2)-dS(N2) = (2 x 210.7) – 205 – 191.5 = 24.9 J/Kmol

For the third reaction,

dS = dS(C2H4) + dS(H2O) – dS(CH3CH2OH) = 219.5 + 188.7 – 160.7 J/Kmol = 247.5 J/mol

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