Question

Question 1 (1 point) In a free-fall experiment, a student measures g to be 10.03 m/s2 with an uncertainty of 0.17 m/s2. The standard value is 9.80 m/s2 with an uncertainty of 0.03 m/s2. The measured value does not agree with the standard value within uncertainties. A) True B) False Hide hint for Question 1

Answer 1

Measured values: - g = 10.3 m/s^2 delta g = 0.17 m/s^2 delta g/g times 100 = 0.17/10.3 times 100 value of g = (10.3 plusminus 0.17) m/s^2 = 9.86 or 10.2 m/s^2 = (10.03 plusminus 1.69%) m/s^2 The standard value g = 9.80 m/s^2 delta g = 0.03 m/s^2 delta g/g times 100 = 0.03/9.80 times 100 = 0.31% value of g = (9.80 plusminus 0.03) m/s^2 = 9.83 or 9.77 m/s^2 = (9.8 plusminus 0.31%) m/s^2 so the measured value does not agree with the standard value within uncertainty (9.86 > 9.13 m/s^2) option (A) is correct.