How do you solve for Q in the following equation: 200 - 50log(Q/2) = 3Q2- 20Q

Question

Question

How do you solve for Q in the following equation:

200 - 50log(Q/2) = 3Q²- 20Q

Answer 1

Answer #1

Consider:

og Q=2e e-322-202 200-50x = 3(*)2-20(2) 200-50log30-200 12g-40ex + 50x 200

Now, consider hit-and-trial method to obtain the value of x

The result is:

1379487 173 33581 238 3 4132 2 7889 2 3 8 5 01123456123 1233 123

Thus, at x=1.65087, the given equation is satisfied

Thus,

Q=2e 2x 165087) = 10.42302

Answer 2

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