Question

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Question 6 10 pts A spring has a spring constant of 20 N/m. How much work is done when the spring stretches a distance of 2 cm? You must show work to earn credit for your answer. HTML Editor D. !!

Answer 1

Question-6

workdone w is given by

$w = \int dw = \int F(x)dx$

spring force F(x) = k x , where k is spring constant and x is stretched length

hence workdone is

$w = \int_{0}^{x} F(s)ds = \int_{0}^{x} k sds = \frac{1}{2} k x^{2} = 0.5 \times 18\times \left ( 2\times 10^{-2} \right )^{2} = 36\times 10^{-4} J$

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Question-8

Force = k x = 18 $\times$ 38.4 $\times$ 10^-2 N = 6.912 N