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Question 16 10 pts A mass of 7 kg attached to a vertical spring stretches the spring 7 cm from its original equilibrium posit

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Solution mass allached m= 7 kg. F-KY Downward force on spring = due to maps = mag = 7x 9.0 = 68-6N new Y = 7cm Now force mg iI Frequency of the system of fat ! 0.531 = 1.88 H₂ f = 1.88 Hz

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