Question

Write a simple Python program to find the day for the given date. The procedure to find the day of the week is as follows:   

F = (K + (13 * m – 1) mod 5 + D + D mod 4 + C mod 4 – 2 * C ) mod 7

where, K : day of the month

m : month number

D : remainder when year divided by 100

C : quotient when year is divided by 100

Note: month is counted as follows: March is 1

April is 2 ……

January is 11

February is 12

So, the year starts from March and ends in February. So, if you have a month as January or February, then subtract 1 from the year.

Example 1: if the entered date is 1st January 2000, then:

K = 1

m = 11

D = (2000 -1 ) mod 100 = 99

C = (2000 -1 ) quotient 100 = 19

F = (1 + (13 * 11 – 1) mod 5 + 99 + 99 mod 4 + 19 mod 4 – 2 * 19 ) mod 7

= 6

If the value of F is:
0 : Sunday

1 : Monday

2 : Tuesday

3 : Wednesday

4 : Thursday

5 : Friday

6 : Saturday

So, the data 1st January 2000 is Saturday.

Example 2: if the entered date is 1st April 1983, then:

K = 1

m = 2

D = 1983 mod 100 = 83

C = 1983 quotient 100 = 19

F = (1 + (13 * 2 – 1) mod 5 + 83 + 83 mod 4 + 19 mod 4 – 2 * 19 ) mod 7

= 5

So, the data 1st April 1983 is Friday.

Sample Test Data:

Please enter the date: 2nd March, 2004

Sample Output:

The day is Tuesday

Answer 1

CODE IN PYTHON:

date = int(input("Enter a date:"))
month = input("Enter a month:")
year = int(input("Enter a year:"))

month = month.upper()

monthList = ["MARCH", "APRIL", "MAY", "JUNE", "JULY", "AUGUST", "SEPTEMBER", "OCTOBER", "NOVEMBER", "DECEMBER", "JANUARY", "FEBRUARY"]
m = monthList.index(month) + 1

k = date
d = year % 100
c = year // 100
f = (k + (13 * m - 1) % 5 + d + d % 4 + c % 4 - 2 * c ) % 7

weekDays = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]

dayString = weekDays[f-1]
print("The day is",dayString)

INDENTATION:

OUTPUT: