Question

in python

Worth 5 points (Science: day of the week) Zeller's congruence is an algorithm developed by Christian Zeller to calculate the day of the week. The formula is h= (q + 26(m+1)//10 + k + k//4 +j//4 +5j) % 7 where - h is the day of the week (0: Saturday, 1: Sunday, 2: Monday, 3: Tuesday, 4: Wednesday, 5: Thursday, 6: Friday). - is the day of the month. m is the month (3: March, 4: April, ..., 12: December). January and February are counted as months 13 and 14 of the previous year. - jis year//100. - k is the year of the century (i.e., year % 100). Write a program that prompts the user to enter a year, month, and day of the month, and then it displays the name of the day of the week. Sample Run 1 Enter year: (e.g., 2008): 2013 Enter month: 1-12: 1 Enter the day of the month: 1-31: 25 Day of the week is Friday Sample Run 2 Enter year: (e.g., 2008): 2012 Enter month: 1-12: 5 Enter the day of the month: 1-31: 12 Day of the week is Saturday Hint: Use the Il operator for integer division. January and February are counted as 13 and 14 in the formula, so you need to convert the user input 1 to 13 and 2 to 14 for the month and change the year to the previous year.

Answer 1

Program to implement Zeller's Congruence.

Python Code:

# Program to implement Zeller's Congruence.
# Written in Python 3

#Take input from the user
y = int(input("Enter year: (e.g., 2008): "))

m = int(input("Enter month: 1-12: "))
if m==1:
    m=13
    y=y-1
elif m==2:
    m=14
    y=y-1
# extra processing for Jan and Feb, we also subtract one from year

q = int(input("Enter the day of month: 1-31: "))

j = y//100 
k = y%100

h = (q +(26*(m+1))//10 +k +k//4 +j//4 +(5*j)) % 7
#calculate the day of week by the Zeller's Congruence

week =["Saturday","Sunday","Monday","Tuesday","Wednesday","Thursday","Friday"] #listofweeks
print("Day of week is: ", week[h] )
#print the result

Screenshot of Output:

Shell Enter year: (e.g., 2008): 2013 Enter month: 1-12: 1 Enter the day of month: 1-31: 25 Day of week is: Friday

Sample inputs are mentioned in question.