PYTHON
I need some basic python homework help!
Write a program that prompts the user to enter a date (day, month, and year). Your program will print out the day of the week for that date.
You do not need to validate the input. That means you can assume:
Algorithm:
This algorithm is called "Zeller's Congruence" after the person who developed it, Rev. Christian Zeller.
Some sample calculations: for July 31, 1929, you should get a = 5, b = 31, c = 29, and d = 19. Similarly, for January 3, 1988, you should get a = 11, b = 3, c = 87, and d = 19.
Then calculate the following quantities:
w = (13 * a - 1 ) // 5 x = c // 4 y = d // 4 z = w + x + y + b + c - 2 * d r = z % 7 r = (r + 7) % 7 [to take care of negative values of r]
If you did this correctly, r gives you the day of the week. r = 0 represents Sunday, r = 1 represents Monday, and so on.
#Zeller Congruence
def day(r):
return {
0 : "Sunday",
1 : "Monday",
2 : "Tuesday",
3 : "Wednesday",
4 : "Thursday",
5 : "Friday",
6 : "Saturday"
}[r]
month=input("Enter Month-")
date=int(input("Enter date-"))
year=int(input("Enter year-"))
monthValue = {'January': 11 , 'February':
12,'March':1,'April':2,'May':3,'June':4,'July':5,'August':6,'September':7,'October':8,'November':9,'December':10}
#python dictionary is created according to the value of
every month.
a=monthValue.get(month)
b=date
if month=='January' or month=='February':
year=year-1
c=year%100 #to get the last 2 digits of the
year
d=year//100 #to get the first 2 digits of the year
w=(13*a-1)//5
x=c//4
y=d//4
z=w+x+y+b+c-2*d
r=z%7
r=(r+7)%7
print(day (r)) # the value r is a integer to get the corresponding day of the week the above function day is created.
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PYTHON I need some basic python homework help! Write a program that prompts the user to...
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