using this problem as an example, does x always = 10^-ph or is there a special case, if so what is that special case? thanks! this is for an ice table if that isn't clear
using this problem as an example, does x always = 10^-ph or is there a special...
7. Butyric acid is responsible for the odor in rancid butter. A solution of 0.25 M butyric acid has a pH of 2.71. What is the Ka for the acid? A. 0.36 B. 2.4 x 10-2 C. 7.8 x 10-3 D. 1.5 x 10-5 E. None of these choices are correct. 8. Lactic acid has a pKa of 3.08. What is the approximate degree of dissociation of a 0.35 M solution of lactic acid? A. 1.1% B. 2.2% C. 4.8%...
What is the answer for 11, 12, and 14? and please show how you calculate it! 11). (4 pts) What is the approximate degree of dissociation of a 0.5 M solution of butyric acid? 10g LHT Butyric acid is responsible for the odor in rancid butter and has a pKa of 4.82. 109ci.61x(0 A) 0.55 % B)4.5 % C) 5.5 % D) 99.9% E) None of these choices are correct. 12). (4 pts) has a pH of 1.9. What is...
If the Ka of a monoprotic weak acid is 2.4 x 10-6, what is the pH of a 0.45 M solution of this acid? pH =
The Ka of hydrazoic acid (HN3) is 1.9 x 10-5 at 25°C. What is the pH of a 0.35 M solution of HN3? 2.59 5.23 2.41 O 1.14
HA is a weak acid. Its ionization constant, Ka, is 2.4 x 10-13. Calculate the pH of an aqueous solution with an initial NaA concentration of 0.046 M.
12. Given that Ka = 1.8 x 10- for acetic acid. in order for an acetic acid solution to have a pH of 3.50, its molar concentration must be a. 5.7 x 10-3 M b. 5.6 x 10-3M c. 3.2 x 10-4M d. 2.3 x 10-M 13. If enough base is added to a solution to cause the pH to increase from 7.50 to 8.50, this means that А a. [OH-] increases by a factor of 10 b. [H'] increases...
i need help solving for y. how did we get 2.4 x 10 ^-8 M here is all the information i need help on how we solved for y = [C2O4^2-]. dont know what to do with 6.4 x 10 ^ -5 = (y)(0.0528 + y) / 0.0528 - y i need a step by step explanation please Reaction [H2CO3] Initia [HCO3) 4.58 x 10-3 -y 0.00458 - y TOH-1 0.00458 +y Change + y Equilibrium 0.00458 + y •...