Question

#5

vyme 14.55 a NAOH Take 3.0L SUTULUI. -TU UUU - 0,557 L soln 3.01 5. Calculate the mass of silver nitrate in 185 mL of a 2.50 M solution. Ag Nog=169.91 g mol = 918 6 Calculate the late in needed to make a 10M solution of sugar given 20.0 mL of 1959 он -

Answer 1

The molar mass i.e mass of 1 mole of Silver nitrate (AgNO3) = 169.87 g/mol

Now the given concentration of AgNO3 solution = 2.50 M = 2.50 mols/ 1000 ml

Given volume of AgNO3 solution = 185 ml

Thus total number of moles of AgNO3 in the solution = concentration * volume

= 2.50 mols/ 1000 ml * 185 ml

= 0.4625‬ moles

Thus mass of 0.4625 mole of Silver nitrate (AgNO3) = number of moles * molar mass

= 0.4625 moles * 169.87 g/mol

= 78.56 g

Hence the mass of AgNO3 in the solution is 78.56 g