Calculate the heart of formation for aluminum chloride using the following thermochemical equations: 2Al (s) +...

Question

Question

Calculate the heart of formation for aluminum chloride using the following thermochemical equations:

2Al _(s) + 6HCl _(aq) ---> 2AlCl_3
(aq) + 3H_{2 (g) .}ΔH = -1049 kJ

HCl (g) ---> HCl (aq) . ΔH = -74.8 kJ

H_{2 (g)} + Cl_{2 (g)} ---> 2HCl (g) ΔH = -1845 kJ

AlCl_{3 (s)} ---> AlCl_{3 (aq)} ΔH = -323 kJ

Answer 1

Answer #1

I Als) + 6 HCl 2 AlCl3(02) + 3H219) Ahz 7049 kJ Ha (9) - HCl (aq) on = -74.0ks H2 (9) + Cl2(g) → 2HA (9) An 2-1845 ks AlCl3 (

Answer 2

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