As given in the problem -
g(Mars) = 3.75 m/s^2
Height of the cliff, h = 85.0 m
Also given that -
v(f) = sqrt(2*g*h)--------------------------------------------(i)
You can simply put the value of variables in equation (i) and you will get the value of v(f).
But before this, I want to show you from where equation (i) is derived.
Use the expression -
v2^2 = v1^2 + 2*a*s
Initially, initial velocity, v1 = 0
Acceleration, a = g
s = h
and of course, v2 = vf
So, put the values we get -
vf^2 = 0 + 2*g*h
=> vf = sqrt(2*g*h)
So again put the values as given in the problem -
vf = sqrt(2*3.75*85.0) = 25.25 m/s
Hence, the speed of the rock when it hits the surface = 25.25 m/s
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